25a^2+25ac-14c^2=0

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Solution for 25a^2+25ac-14c^2=0 equation: 


Simplifying
25a2 + 25ac + -14c2 = 0

Reorder the terms:
25ac + 25a2 + -14c2 = 0

Solving
25ac + 25a2 + -14c2 = 0

Solving for variable 'a'.

Factor a trinomial.
(5a + -2c)(5a + 7c) = 0


Subproblem 1
Set the factor '(5a + -2c)' equal to zero and attempt to solve:

Simplifying
5a + -2c = 0

Solving
5a + -2c = 0

Move all terms containing a to the left, all other terms to the right.

Add '2c' to each side of the equation.
5a + -2c + 2c = 0 + 2c

Combine like terms: -2c + 2c = 0
5a + 0 = 0 + 2c
5a = 0 + 2c
Remove the zero:
5a = 2c

Divide each side by '5'.
a = 0.4c

Simplifying
a = 0.4c

Subproblem 2
Set the factor '(5a + 7c)' equal to zero and attempt to solve:

Simplifying
5a + 7c = 0

Solving
5a + 7c = 0

Move all terms containing a to the left, all other terms to the right.

Add '-7c' to each side of the equation.
5a + 7c + -7c = 0 + -7c

Combine like terms: 7c + -7c = 0
5a + 0 = 0 + -7c
5a = 0 + -7c
Remove the zero:
5a = -7c

Divide each side by '5'.
a = -1.4c

Simplifying
a = -1.4c
Solution
a = {0.4c, -1.4c}

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